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Molecular formula and valency - class-VII

Description: molecular formula and valency
Number of Questions: 20
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Tags: composition of matter atoms and molecules atoms, molecules and radicals the language of chemistry chemistry atoms, molecules and chemical reactions
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Quantitatively, formula represents:

  1. One molecule of the substance.

  2. The actual number of atoms of each element in one molecule of the substance.

  3. The number of parts by weight of the substance (molecular weight).

  4. The number of parts by weight of each element.


Correct Option: A,B,C,D
Explanation:

(A) One molecule of the substance

$\longrightarrow$ example $NaCl,C _2H _5OH$

(B) The actual number of atoms of each element in one molecule of the substance.
$\longrightarrow$ example $H _2O$ [water]
It shows that water contains $2$ atoms of hydrogen and $1$ atom of oxygen.

(C) The number by parts by weight of the substance [molecular weight]
$\longrightarrow$ Molecular weight can be determined by chemical formula as shown below:-
$CO _2$
one atom of carbon $\times$ mass of carbon + $2$ atoms of oxygen $\times$ mass of oxygen
$=1\times 12+2\times 16$
$=12+32$
$=44g/mol$.

(D) The number of parts by weight of each element $\longrightarrow$ example (1) $C _2H _5OH$ [ethanol] Molecular mass= $46$
(i) Each mole of ethanol contains $2$ moles of carbon
$=12\times2$
$=24g$
(ii) $1$ mole of oxygen atom
$=16\times 1$
$=16g$
(iii) $6$ moles of hydrogen atom
$=1\times 6$
$=6g$
These are present in $46g$ of ethanol
$\therefore$ Percentage of carbon=$\cfrac {24}{46}\times 100=52.17$%
Percentage of oxygen=$\cfrac {16}{46}\times 100=34.78$%
Percentage of hydrogen=$\cfrac {6}{46}\times 100=13.05$%

The formula of iron (III) sulphate is:

  1. $Fe _3CO _4$

  2. $Fe _2(SO _4) _3$

  3. $Fe _2(CO _4) _3$

  4. $FeCO _4$


Correct Option: B
Explanation:

It is given that the valency of iron in iron sulphate is $+3$ and we know that for sulphate $({SO _4}^{2-})$, it is $-2$. Therefore, the formula is $Fe _2(SO _4) _3$.


$2Fe^{+3} +3{SO _4}^{-2} \rightarrow Fe _2(SO _4) _3$
                                  Iron (III) sulphate

Hence, option B is correct.

Two oxides of a metal contain 30.0% and 27.6 % of oxygen respectively. If the formula of the first oxide is $M _3O _4$, the formula of the second oxide, is

  1. $M _2O _3$

  2. $M _4O _3$

  3. $M _3O _4$

  4. $M _3O _2$


Correct Option: A
Explanation:

Formula of first oxide = $M _3O _4$ 
let mass of the metal be = x
percentage of metal in $\displaystyle M _3O _4 = \frac{3x}{ 3x+64}\times100$
but % age = (100-27.6) = 72.4 %
so, $\displaystyle \frac{3x}{ 3x+64}\times100$
or x = 56.
in 2nd oxide,
oxygen = 30%....so metal = 70%
so, ratio :--
M : O
70/56 : 30/16
1.25 : 1.875
2 : 3
so, 2nd oxide =$ M _2O _3$

The formula for potassium permanganate is:

  1. ${ K } _{ 2 }{ MnO } _{ 4 }$

  2. ${ K }{ MnO } _{ 4 }$

  3. ${ K } _{ 2 }{ Mn } _{ 2 }{ O } _{ 4 }$

  4. ${ K }{ Mn } _{ 2 }{ O } _{ 4 }$


Correct Option: B
Explanation:

Potassium permangnate is a strong oxidizing agent and an inorganic chemical compound which is used in titrations. It has formula ${ KMnO } _{ 4}\ consisting\ of\ { K }^{ + },{ MnO } _{ 4 }^{ - }\quad ions.$ In this compound manganese is in $+7$ oxidation state.

Chemical formula of few compounds are given.
(i) $Zn(PO _4) _2$ (ii) $Fe _2S _3$ (iii) $AlN$ (iv) $Ca(HCO _3)$ (v) $K _2SO _4$.

The wrong chemical formulas are :

  1. (ii) and (iii)

  2. (i), (iv) and (v)

  3. (i) and (iv)

  4. (i), (ii), (iii), (iv), (v)


Correct Option: C
Explanation:

Correct chemical formula's
(i) $Zn _3(PO _4) _2$ 
(ii) $Fe _2S _3$
(iii) $AlN$ 
(iv) $Ca(HCO _3) _2$ 
(v) $K _2SO _4$.

Which of the following chemical formulae of compounds given are wrong:


(i) $Zn(SO _4)$ (ii) $SFe$ (iii) $MgN _3$ (iv) $Ca(OH) _2$ (v) $KCl$.

  1. (ii) and (iii)

  2. (i), (iv) and (v)

  3. (i) and (iv)

  4. (i), (ii), (iii), (iv), (v)


Correct Option: A
Explanation:

Correct chemical formula's
(i) $ZnSO _4$ 
(ii) $Fe _2S _3$
(iii) $Mg _3N _2$ 
(iv) $Ca(HO) _2$ 
(v) $KCl$.

Electrovalencies of three metals $A, B, C $are $1, 2, 3$ respectively and those of non-metals $X, Y, Z$ and $3, 2, 1$ respectively. Which among the following couldn't be the formula of the various ionic compounds formed between the respective metals and non-metals?

  1. $A _3 X, BY, CZ _3$

  2. $AZ, B _3 X _2, C _2 Y _3$

  3. $AZ _3, B _2X, C _3Y _2$

  4. $A _2Y, BZ _2, CX$


Correct Option: C
Explanation:

The incorrect formula's are; $AZ _{3}$, $B _{2}X$, $C _{3}Y _{2}$

The formula of calcium dihydrogen phosphate is :

  1. $Ca(H _2 PO _4) _2$

  2. $Ca(HPO _4) _2$

  3. $Ca _3HPO _4$

  4. $Ca _3(H _2 PO _4) _2$


Correct Option: A
Explanation:

 $Ca^{2+}$ ion and $H _{2}PO _{4}^{-1}$ ion combine to form $Ca(H _{2}PO _{4}) _{2}$

The formula of hydrogen phosphate of a metal M is MHPO$ _4$. Give the formula of metal chloride.

  1. $MCl$

  2. $MCl _3$

  3. $MCl _2$

  4. $M _2$Cl


Correct Option: C
Explanation:

$MHPO _4$ is derived from the acid $H _{3}PO _{4}$ . Thus the metal $M$ replaced two hydrogen atoms of hydrogen phosphate. So, its valency is $2.$ Hence the formula of the metal chloride is $MCl _{2}$ . (Because the valency of$ M$ is $2$ and the valency of$ Cl$ is $1$

Identify the incorrect formula among the following :

  1. $(NH _4) _2 HPO _4$

  2. $PbO _2$

  3. $CaHSO _4$

  4. $BaO _2$


Correct Option: C
Explanation:

Option(C) is incorrect. It can be $CaSO _{4}$ and not  $CaHSO _{4}$.

A formula tells about :

  1. number of atoms present in one molecule

  2. gives mathematical formula

  3. an element

  4. the source of the compound


Correct Option: A
Explanation:

Molecular formulas describe the exact number and type of atoms in a single molecule of a compound. The constituent elements are represented by their chemical symbols, and the number of atoms of each element present in each molecule is shown as a subscript following that element's symbol. The molecular formula expresses information about the proportions of atoms that constitute a particular chemical compound, using a single line of chemical element symbols and numbers. Sometimes it also includes other symbols, such as parentheses, dashes, brackets, and plus (+) and minus (–) signs.

The molecular formula is a short form representation of

  1. A compound

  2. An element

  3. A mixture

  4. An alloy


Correct Option: A
Explanation:

 A chemical formula that shows the total number and kinds of atoms in a molecule, but not their structural arrangement or the molecular formula is a short form representation of a compound.

When naming a binary compound, what determines the prefix for an element in a compound?

  1. The number of atoms of that element in the compound

  2. The number of valence electrons in the element

  3. The total number of atoms in the compound

  4. The number of shared electrons in the compound

  5. The number of different elements in the compound


Correct Option: A
Explanation:

When naming a binary compound, the number of atoms of that element in the compound determines the prefix for an element in a compound.
For example, while naming  $N _2O _3 $, the prefix di is used for $N$ which indicates $2 N$ atoms and the prefix tri is used for $O$ which indicates $3 O$ atoms. Hence, the name dintirogen trioxide.

The salt of an oxyacid of a metal M contains one sulphur and four oxygen atoms

The oxyacid of the salt is

  1. $H _{2}SO _{4}$

  2. $H _{2}SO _{3}$

  3. $H _{2}S _{2}O _{7}$

  4. $H _{2}S$


Correct Option: A
Explanation:

The salt of an oxyacid of a metal M contains one sulphur and four oxygen atoms. The oxyacid of the salt is $H _{2}SO _{4}$. One sulphur and four oxygen atoms indicate sulphate ion $(SO _4^{2-})$. Hence, the salt is metal sulphate and the oxyacid is sulphuric acid.

The trivial name of $Na _{2}CO _{3}$ is:

  1. soda ash

  2. soda carb

  3. soda

  4. baking soda


Correct Option: A
Explanation:

Trivial name of $Na _2CO _3\longrightarrow$ Soda Ash

Chemical name of $Na _2CO _3\longrightarrow$ Sodium Carbonate
A chemical formula is of great importance
$\longrightarrow$ Name of compounds are represented by the chemical formula.
Example: Sodium bicarbonate$\longrightarrow NaHCO _3$
Sulphuric acid $\longrightarrow H _2SO _4$
$\longrightarrow$ It is known by chemical formula how many atoms of a particular element are present in the compound.
Example: Phosphoric acid
$H _3PO _4$ shows that there are $3$ atoms of hydrogen, $1$ atom of Phosphorus and $4$ atoms of oxygen.
$\longrightarrow$ It represents what elements are present in the compound by its symbol.
Example:- $NaCl\longrightarrow$ Sodium chloride has sodium and chlorine in it.

The general formula of one molecule of a metallic halide can be

  1. MX

  2. $MX _{2}$

  3. $MX _{3}$

  4. $M _{2}X$


Correct Option: A,B,C
Explanation:

The general formula of one molecule of a metallic halide can be-

$MX = NaCl$
$MX _2 =MgCl _2$
$MX _3 = AlCl _3$
All halogens are monovalent hens $M _2X$ is not possible.

The chemical formula of the compound containing carbon and chlorine is:

  1. $CCl _2$

  2. $CCl _3$

  3. $CCl _4$

  4. $C _2Cl _4$


Correct Option: C
Explanation:

Carbon has a valency of$ +4$ and chlorine has a valency equal to $-1. $Compound is Carbon tetrachloride $CCl _4$.

Predict the formulae of the binary compounds formed by combination of the following pairs of elements:
(i)    Magnesium and nitrogen
(ii)   Silicon and oxygen

  1. $MgN _{2}, SiO _{2}$

  2. $Mg _{3}N _{2}, SiO _{2}$

  3. $Mg _{2}N _{3}, Si _{2}O _{3}$

  4. $MgN, SiO _{2}$


Correct Option: B
Explanation:

Three Mg ( $+2$ oxidation state) combine with two N ($-3$ oxidation state) to form $Mg _3N _2$.

One Si ( $+4$ oxidation state) combine with two O ($-2$ oxidation state) to form $SiO _2$.

Note: In a neutral molecule, the total charge on cations is numerically equal to the total charge on anions.

Predict the formula of stable compound formed by an element with atomic number 114 and fluorine.

  1. $AF _{3}$

  2. $AF _{2}$

  3. $AF$

  4. $AF _{4}$


Correct Option: D
Explanation:
Element A with atomic number 114 will share four electrons to attain stable noble gas electronic configuration. It falls in the Carbon family.

Fluorine shares one electron to attain stable noble gas electronic configuration. One atom of A combines with four atoms of F to form $AF _4$.

Hence, the correct option is $\text{D}$
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