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Types of radioactivity - class-X

Description: types of radioactivity
Number of Questions: 19
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Tags: nuclear chemistry and radioactivity nuclear physics physics chemistry
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The radioactive isotope used in the treatment of cancer has to be a good source of ________ radiations.

  1. $\beta$

  2. $\alpha$

  3. $\gamma$

  4. $IR$


Correct Option: C
Explanation:

X-rays, gamma rays and beta particles are all used in medicine to treat internal organs. X-rays are produced by firing electrons at a metal target and gamma rays are emitted by the nucleus of radioactive atoms. Gamma rays are used to kill cancer cells, to sterilize medical equipment and in radioactive tracers.

Match the following

List - I List - II
A) Functioning of Thyroid gland  I) Cobalt - 60
B) Blood disorders  II) Iodine - 131
C) Cancer  III) Sulphur - 35
D) Transportation of minerals in plants  IV) radio phosphorus
V) radio sodium
  1. A-I,III B- II,IV C-III,V D-IV

  2. A-II B-IV,V C-I D-III

  3. A-I B-II C-IV D-III

  4. A-II B-I C-III D-IV


Correct Option: B
Explanation:

 1.Iodine - 131 it is use for functioning of Thyroid gland. It detect using radio active Iodine - 131

2.Radioactive phosphorus is known as P-32. It is a radioactive form of sodium phosphate. It is used as a treatment for some blood disorders.

3.Cobalt therapy or cobalt-60 therapy is the medical use of gamma rays from the radioisotope cobalt-60 to treat conditions such as cancer.

4.The sulfate ions in the solution contained radioactive sulfur atoms – 35 S. The purpose of this investigation was to investigate active transport, that is, a process that uses energy to transport useful substances across cell membranes.

 

The count rate observed from a radioactive source at $t$ second was $N _0$ and at $4t$ second it was $\dfrac{N _0}{16}$. The count rate observed at $\left(\dfrac{11}{2}\right)t$ second will be

  1. $\dfrac{N _0}{128}$

  2. $\dfrac{N _0}{64}$

  3. $\dfrac{N _0}{32}$

  4. $None\ of\ these$


Correct Option: B
Explanation:
after n lives,

$N=N _0\left ( \dfrac{1}{2} \right )$

initially,

$t=t$

$t=4t-t=3t$

$\dfrac{N _0}{16}=N _0\left ( \dfrac{1}{2} \right )^n$

$n=4$

$4t _{\frac{1}{2}}=3t$

$\Rightarrow t _{\frac{1}{2}}=\dfrac{3}{4}t$

$\lambda =\dfrac{\ln 2}{t _{\frac{1}{2}}}=\dfrac{4\ln 2}{3t}$

at $t=\dfrac{11}{2}ts$

$t=\dfrac{11}{2}t-t=\dfrac{9}{2}t$

$N=N _0e^{-\lambda \frac{9}{2}t}$

$N=N _0e^{-\lambda \frac{4\ln 2}{3t}\times \frac{9}{2}t}$

$N=N _0e^{-6\ln 2}$

$N=N _0e^{\ln \frac{1}{2^6}}$

$N=\dfrac {N _0}{2^6}=\dfrac {N _0}{64}$

After $280$ days, the activity of a radioactive sample is $6000 dps$. The activity reduces to $3000 dps$ after another $140 days$. The initial activity of the sample in $dps$ is:

  1. $6000$

  2. $9000$

  3. $3000$

  4. $24000$


Correct Option: D
Explanation:

Here, the activity of the radioactive sample reduces to half in $140$ days. Therefore, the half life of the sample is $140$ days. $280$ days is it's two half lives. So before two half lives it's activity was

${2^6} \times 6000 = 24000\,dps.$
Hence, the option $D$ is the correct answer.

The specific activity (per gm) of radium is nearly-

  1. 1 Bq

  2. 11 Ci

  3. $ 3.7 \times 10^{10} Bq$

  4. 1 m Ci


Correct Option: C

The radioactivity of an old sample of a liquid due to tritium (half life $12.5$ years) was found to be only about $3$% of that measured in a recently purchased bottle marked $7$ year old. The sample must have been prepared about:

  1. $70$ year

  2. $63.24$ year

  3. $420$ year

  4. $300$ year


Correct Option: B
Explanation:

$\begin{array}{l} Hence, \ \frac { N }{ { { N _{ 0 } } } } =0.03=\left( { -\lambda t } \right)  \ In\left( { 0.03 } \right) =-\lambda t=\frac { { -In\left( 2 \right) \times t } }{ { \frac { { { T _{ 1 } } } }{ 2 }  } }  \ t=\frac { { In\left( { 0.03 } \right) \times \frac { { { T _{ 1 } } } }{ 2 }  } }{ { -In\left( 2 \right)  } } =63.24\, years \end{array}$

Hence,
option $(B)$ is correct answer.

Radioactive nuclei injected into a patient collect at certain sites within the body,undergo radioactive decay and emit electromagnetic radiation.These radiations can then be recorded by a detector.This procedure provides an important diagnostic toll called

  1. Gamma camera

  2. CAT scan

  3. Radio tracer technique

  4. Gamma ray spectroscopy


Correct Option: C
Explanation:

Tracers are a common application of radioisotopes. A tracer is a radioactive element whose pathway through which a chemical reaction can be followed. Tracers are commonly used in the medical field and in the study of plants and animals. Radioactive Iodine-131 can be used to study the function of the thyroid gland assisting in detecting disease.

Fill in the blanks :

The mass of a body remains constant till the velocity of body is ............

  1. much less than the velocity of light

  2. equal to velocity of light

  3. much higher than the velocity of light

  4. none of the above


Correct Option: A
Explanation:

According to Einstein if a body moves almost more than the velocity of light then it starts losing its mass.He gave this concept by a formula that is $E=m c^{2}$.Hence for the body to maintain constant mass it has to move with the speed less than the velocity of light.

The atomic number of natural radioactive element is .....................

  1. greater than 82

  2. less than 82

  3. not defined

  4. atleast 92


Correct Option: A
Explanation:

A

All elements with atomic numbers greater than 83 are radio isotope meaning that these elements have unstable nuclei and are radioactive. 

Which of the following can be diagnosed by Iodine-131 radioisotope?

  1. Kidneys

  2. Heart

  3. Lungs

  4. Thyroid

  5. Bone marrow


Correct Option: D
Explanation:

Iodine in food is absorbed by the body and preferentially concentrated in the thyroid where it is needed for the functioning of that gland. Thus the health problem related to thyroid can be diagnosed by Iodine−131 radioisotope. 

The electromagnetic radiation observed in Radioactivity is ..............

  1. $\alpha$ - particle

  2. $\beta$ - particle

  3. $\gamma$ - rays

  4. X - rays


Correct Option: C
Explanation:

Gamma ray (also called gamma radiation) is penetrating electromagnetic radiation of a kind arising from the radioactive decay of atomic nuclei. It consists of photons in the highest observed range of photon energy.

Alpha particles have________kinetic energy and momentum with them. Fill in the blank. 

  1. less

  2. large

  3. no

  4. all of the above


Correct Option: B
Explanation:

Alpha particles have large kinetic energy and momentum with them. They are used to bombard the atomic nuclei to convert one element into another (for transmutation)

Nearly all isotopes of elements having mass number _______ are radioactive. 
  1. Lower than 82

  2. Higher than 82

  3. Higher than 69

  4. Lower than 69


Correct Option: B
Explanation:

The isotopes of nearly all the elements of atomic number higher than 82 (i.e. lead) are radioactive. There are called the natural radioactive substances.

Which of the following is a radioactive substance?

  1. Uranium

  2. Radium

  3. Thorium

  4. All of the above 


Correct Option: D
Explanation:

Substances which disintegrate (or decay) by the spontaneous emission of radiations are called the radioactive substances. Eq. Uranium, radium, polonium, thorium, actinium etc.

Which of the following statements are true?

  1. The nucleus of an atom becomes radioactive when A - Z is more than Z

  2. Isotopes having radioactive properties are called radio isotopes

  3. Radio isotopes can be prepared artifically by nuclear transmutation

  4. All of the above


Correct Option: D
Explanation:

The atoms having radioactive properties are called radio isotopes. The nucleus of an atom becomes radioactive when the number of neutrons in the nucleus exceeds the number of protons inside it. $ _{6}C^{14},  _{27}Co^{60},  _{6}C^{12},  _{19}K^{40}$ etc are all examples of naturally occurring radio isotopes. However, they can also be prepared artificially by nuclear transmutation.

The age of fossils can be estimated with the help of which radioisotope?

  1. $ _{6}C^{14}$

  2. $ _{27}Co^{60}$

  3. $ _{6}C^{12}$

  4. $ _{19}K^{40}$


Correct Option: A
Explanation:

The age of fossils can be estimated by the study of decay of radioactive carbon atom $ _{6}C^{14}$ in the remains of the dead and decaying material. This process is called carbon dating.

Rate of decay of radioactive substance is altered by :

  1. pressure

  2. temperature

  3. chemical change

  4. none of the above 


Correct Option: D
Explanation:

Any physical changes (temperature, pressure and temperatures) or chemical changes do not alter the rate of decay of the radioactive substances.

Which of the following is used by an archaeologist to determine the age of an artifact, in percentage?

  1. $Carbon-14$

  2. $Phosphorus-31$

  3. $Hydrogen-3$

  4. $Chlorine-37$

  5. $Bromine-81$


Correct Option: A
Explanation:

Carbon−14 is used by an archaeologist to determine the age of an artifact, in percentage.
The ratio C-14 / C-12 in fresh sample is compared with the ratio in dead sample.

The radioactivity of a sample is $R _ { 1 } $at a time $T _ { 1 }$ and $R _ 2$ at a time $ T _ 2 $ . If the half-life of the specimen is T  ,  the number of atoms that have disintegrated in the time $T _ 2 - T _  1 $ is proportional to 

  1. $T _2-T _1\alpha(R _1-R _2)T$

  2. $\left( R _ { 1 } - R _ { 2 } \right)$

  3. $\left( R _ { 1 } - R _ { 2 } \right) / T$

  4. $\left( R _ { 1 } - R _ { 2 } \right) T$


Correct Option: A
Explanation:
[D]
$\begin{array}{l} { R _{ 1 } }=\lambda { N _{ 1 } } \\ { R _{ 2 } }=\lambda { N _{ 2 } } \end{array}$
Number of atoms disintegrated in time 
$\begin{array}{l} { T _{ 2 } }-{ T _{ 1 } }={ N _{ 1 } }-{ N _{ 2 } }=\dfrac { { { R _{ 1 } }-{ R _{ 2 } } } }{ \lambda  }  \\ \lambda =\dfrac { { 0.693 } }{ T }  \\ { T _{ 2 } }-{ T _{ 1 } }=\dfrac { { { R _{ 1 } }-{ R _{ 2 } }\times T } }{ { 0.693 } }  \\ { T _{ 2 } }-{ T _{ 1 } }\alpha \left( { { R _{ 1 } }-{ R _{ 2 } } } \right) T \end{array}$
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