Energy in wave motion - class-XI
Description: energy in wave motion | |
Number of Questions: 19 | |
Created by: Mohini Tyagi | |
Tags: physics oscillation and waves waves |
If the energy density and velocity of a wave are $u$ and $c$ respectively then the energy propagating per second per unit area will be
The kinetic energy per unit length for a wave on a string is the positional coordinate
A travelling wave has an equation of the form $A(x,t)=f(x+vt)$. The relation connecting positional derivative with time derivative of the function is:
Kinetic energy per unit length for a particle in a standing wave is zero at:
The total energy per unit length for a travelling wave in a string of mass density $\mu$ , whose wave function is $A(x,t) = f(x \pm vt)$ is given by:
The maximum potential energy / length increases with:
In the absence of a wave travelling on a tight rope fixed at both the ends, the potential energy per unit length on the rope is zero.
Potential energy of a string depends on
The wave number of energy emitted when electron jumps from fourth orbit to seconds orbit in hydrohen in $20,497\ cm^{-1}$. The wave number of energy for the same transition in $He^{+}$ is
The ends of a stretched string of length $L$ are fixed at $x=0$ and $x=L$. In one experiment, the displacement of the wire is $y _{1}=2A\sin\left(\dfrac{\pi x}{L}\right)\sin\omega t$ and energy $E _1$ and in another experiment, its displacement is $y _2 = A\sin\left({\displaystyle\frac{2\pi x}{L}}\right)\sin{2\omega t}$ and energy $E _2$ then
If the frequency and amplitude of a transverse wave on a string are both doubled, then the amount of energy transmitted through the string is
A string of per unit length $\mu$ is clamped at both ends such that one end of the string is at $x = 0$ and the other is at $x = \ell$. When string vibrates in fundamental mode amplitude of the mid-point of the string is a and tension in the tension in the string is $T$. If the total oscillation energy stored in the string is $\displaystyle \,\frac{\pi^2\,a^2\,T}{xl}$. Then the value of $x$ is
$y _1 = 88\, sin(\omega t - kx)$ and $y _2 = 6 sin(\omega t + kx)$ are two waves travelling in a string of area of cross-section $s$ and density $\rho$. These two waves are superimposed to produce a standing wave. Find the total amount of energy crossing through a node per second.
Choose the correct alternative(s) regarding standing waves in a string
With the propagation of a longitudinal wave through a material medium, the quantities transmitted in the direction of propagation are
The amplitude of two waves are in ratio 5 : 2. If all other conditions for the two waves are same, then what is the ratio of their energy densities?
A progressive wave on a string having linear mass density $\rho$ is represented by $y = A\sin \left (\dfrac {2\pi}{\lambda} x - \omega t\right )$ where $y$ is in $10\ mm$. Find the total kinetic energy (in $\mu l)$ passing through origin from $t = 0$ to $t = \dfrac {\pi}{2\omega}$.
[Take : $\rho = 3\times 10^{-2} kg/ m; A = 1mm; \omega = 100\ rad/ sec; \lambda = 16\ cm]$
A clamped string is oscillating in nth harmonic, then
To determine the position of a point like object precisely ______ light should be used.