Distance between two parallel planes - class-XII
Description: distance between two parallel planes | |
Number of Questions: 17 | |
Created by: Avani Handa | |
Tags: applications of vector algebra three dimensional geometry - ii maths introduction to three-dimensional geometry |
Distance between the parallel planes $2x-3y+4z-1=0$ and $4x-6y+8z+8=0$ is
Distance between the two planes: $2 x + 3 y + 4 z = 4$ and $4 x + 6 y + 8 z = 12$ is
The distance between the planes $x-2y+3z=6$ and $3x-6y+9z+5=0 is $
The distance between the planes $x + 2y + 3z + 7 = 0$ and $2x + 4y + 6z + 7 = 0$ is
If the distance between the planes $8x + 12y - 14 z = 2$ and $4x + 6y - 7z = 2$ can be expressed in the form $\displaystyle \frac{1}{\sqrt{N}}$, where N is natural, then the value of $\displaystyle \frac{N(N + 1)}{2}$ is
If the distance between the planes $8x + 12y - 14z = 2$ and $4x + 6y - 7z = 2$ can be expressed in the form of $ \displaystyle \frac {1}{ \sqrt N} $ where $N$ is a natural number, then the value of $ \displaystyle \frac { N(N+1)}{2} $ is
If the distance between the planes $8x + 12y - 14z = 2$ and $4x + 6y - 7z = 2$ can be expressed int he form $\dfrac{1}{\sqrt{N}}$ where $N$ is natural, then the value of $\dfrac{N(N+1)}{2}$ is
If ${ p } _{ 1 },{ p } _{ 2 },{ p } _{ 3 }$ denote the distance of the plane $2x-3y+4z+2=0$ from the planes $2x-3y+4z+6=0, 4x-6y+8z+3=0$ and $2x-3y+4z-6=0$ respectively, then
Distance between two parallel planes $2 x + y + 2 x = 8$ and $4 x + 2 y + 4 x + 5 = 0$ is
The distance between the planes $\displaystyle 4x - 5y + 3z = 5$ and $\displaystyle 4x - 5y + 3z + 2 = 0$ is
The distance between the planes $\displaystyle 2x + y + 2z = 8$ and $\displaystyle 4x + 2y + 4z + 5 = 0$ is
The distance between the planes given by $\vec{r}.\left ( i:+:2j:-:2k \right ):+:5= 0$ and $\vec{r}.\left ( i:+:2j:-:2k \right ):-:8= 0$ is
The distance between the parallel planes given by the equations, $\vec{r}\,. \, (2\, \hat{i}\, -\, 2\, \hat{j}\, +\, \hat{k})\, +\, 3\, =\, 0$ and $\vec{r}\,. \, (4\, \hat{i}\, -\, 4\, \hat{j}\, +\, 2\hat{k})\, +\, 5\, =\, 0$ is:
If $P _1\,,\, P _2\,
,\, P _3$ denotes the perpendicular distances of the plane $2x -3y + 4z + 2 = 0$ from the parallel planes $2x- 3y + 4z +6 = 0, 4x -6y + 8z + 3 = 0 $ and $2x- 3y + 4z- 6 = 0$ respectively, then
A line having direction ratios $3,4,5$ cuts $2$ planes $2x-3y+6z-12=0$ and $2x-3y+6z+2=0$ at point P & Q, then Find length of PQ
The distance between the parallel planes $2x+y+2z-8=0 $ and $4x+2y+4z+5=0$ is