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Terms related to lenses - class-X

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Fill in the blank. 

A _____ is a piece of transparent glass bounded by two spherical surfaces. 

  1. lens

  2. mirror

  3. both  

  4. none 


Correct Option: A
Explanation:

A lens is a piece of transparent glass bounded by two spherical surfaces.


Answer is lens.

The focal length of a lens can be expressed in :

  1. metre

  2. dioptre

  3. watt

  4. horse power


Correct Option: A
Explanation:

focal length is basically length from the optic centre to the focus, so it is expressed in metres

A straight line passing through the two centres of curvature of lens is called

  1. Normal

  2. Principal axis

  3. Centre axis

  4. Diameter axis


Correct Option: B
Explanation:

Principal axis is a straight line passing through the two centres of curvature of lens.

The principal axis is also called _______ of the lens.

  1. optical axis

  2. x-axis

  3. y-axis

  4. axis


Correct Option: A
Explanation:

The principal axis is also called optical axis of a lens, passing through the optical center of the lens.

Which of the following term is not associated with a lens ?

  1. Aperture

  2. Focal length

  3. Principal focus

  4. Efficiency


Correct Option: D
Explanation:

Aperture of a lens is the length of the surface of lens exposed for incident light.Focal length is the distance between focus of the lens and lens optical center.Principal focus is the focus from which a ray of light traveling parallel to optical axis passes through or appears to pass through after refraction.There is no term like efficiency of a lens.but there is magnification of a lens.

The value of the focal length of the lens is equal to the value of the image distance when the rays are

  1. Passing through the optic centre

  2. Parallel to the principal axis

  3. Passing throught he focus

  4. Over the mirror


Correct Option: B
Explanation:

When the object is placed at infinity, i.e., when the rays are parallel to the principal axis, the value of focal length is equal to the value of the image distance.

i.e., object distance , $u=\infty$
From lens formula,

$\dfrac 1f=\dfrac 1u+\dfrac 1v\\\implies \dfrac 1f=\dfrac 1\infty+\dfrac 1v\\\implies f=v$
i.e., image distance is equal to focal length of the lens.

Fill in the blanks:

Principal axis is also called ________ of the lens.

  1. Optical axis

  2. x-axis

  3. y-axis

  4. axis


Correct Option: A
Explanation:

Principal axis is also called optical axis of the mirror or lens .

The focal length can be expressed in:

  1. metre

  2. Dioptre

  3. Watt

  4. Horse power


Correct Option: A
Explanation:

The focal length is associated with distance. So, it can be expressed in metre.

Which of the following term is not associated with a lens?

  1. Aperture

  2. Focal length

  3. Principal focus

  4. Momentum


Correct Option: D
Explanation:

The term momentum is not associated with a lens. It is the product of mass and velocity of a body.

A thin plano-convex lens acts like concave mirror of focal length $0.2m$ when silvered at its plane surface. Refractive index of the material of lens is $1.5$. Radius of curvature of convex surface of the lens is

  1. $0.1m$

  2. $0.2m$

  3. $0.4m$

  4. $0.8m$


Correct Option: B

A plane-convex lens has a refractive index of 1.6 and a radius of curvature 60 cm. What is the focal length of the lens? 

  1. 50 cm

  2. 100 cm

  3. 200 cm

  4. 150 cm


Correct Option: B
Explanation:

${R _1} = 60\,cm,\,\,{R _2} = \infty ,\,\,\mu  = 1.6$

$\frac{1}{f} = \left( {\mu  - 1} \right)\left( {\frac{1}{{{R _1}}} - \frac{1}{{{R _2}}}} \right)$
$\frac{1}{f} = \left( {1.6 - 1} \right)\left( {\frac{1}{{60}}} \right)$
$ = f = 100\,cm.$
Hence,
option $(B)$ is correct answer.

Which statement is correct for a zone plate and a lens?

  1. Zone plate has multi focii whereas lens has one

  2. Zone plate has one focus whereas lens has multiple focii

  3. Both are correct

  4. Zone plane has one focus whereas a lens has infinite


Correct Option: A

A small object is placed at a distacne 80 cm to the left of the lens.  The position and nature of image formed due to I lens is 

  1. real, 30 cm right of I lens

  2. virual, 80 cm right of I lens

  3. virtual , 30 cm right of II lens

  4. real, 30 cm right of II lens


Correct Option: C

A point on the principal axis of a lens, to which light rays parallel to the principal axis converge after passing through the lens, is ............

  1. Centre of curvature

  2. Origin

  3. Focus

  4. Optical centre


Correct Option: C
Explanation:

A point on the principal axis of a lens, to which light rays parallel to the principal axis converge after passing through the lens, is  called focus of the lens.


Answer-(C).

For which of the following is $f > 0$:

I. Concave mirror
II. Convex mirror
III. Converging lens
 

  1. I only

  2. II only

  3. I and III only

  4. II and III only

  5. I, II, and III


Correct Option: C
Explanation:

In this style of multiple-choice question, the I, II, and III questions provide you with three possible answers, and the five answer choices list different combinations of those three. Theres an upside and a downside to questions like these. Suppose you know that a concave mirror has f >0 and a convex mirror doesnt, but youre not sure about a converging lens. The downside is that you cant get the right answer for sure. The upside is that you can eliminate B, D, and E, and have a 50% chance of guessing the right answer. As long as youre not afraid to guessand you should never be afraid to guess if youve eliminated an answerthese questions shouldnt be daunting. 
The value of f for a converging lens is positive, so the answer is C . 

Centre point of a lens is called

  1. Centre of curvature

  2. Pole

  3. Origin

  4. Optical centre


Correct Option: D
Explanation:

Centre point of a lens is called the Optical Centre of the lens. Any ray of light passing through it goes un-deviated.


Answer-(D).

A convex and a concave lens separated by distance $d$ are then put in contact. The focal length of the combination

  1. Decreases

  2. Increases

  3. Becomes $0$

  4. Remains the same


Correct Option: A
Explanation:

$\dfrac{1}{f _r}=\dfrac{1}{f _1}+\dfrac{1}{f _2}-\dfrac{d}{f _1f _2}$

So when are brought in contact $d=0$, hence focal length $f _r$ will decrease .

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