Graphs - class-XII
Description: graphs | |
Number of Questions: 15 | |
Created by: Sanjiv Memon | |
Tags: sets, relations and functions differential calculus limits and continuity of a function measurements and uncertainties relations and functions functions and graphs maths physics business maths functions |
If f is even function and g is an odd function, then $f _og$ is ............function.
The identity function on real numbers given by $f(x)=x$ is continuous at every real numbers.
The minimum value of $f\left( x \right) ={ x }^{ 2 }+2x+3 ,x\in R$ is equal to
Years | Production of Car P | Production of Car Q | Production of Car R |
---|---|---|---|
2001 | 76 | 59 | 28 |
2002 | 82 | 62 | 36 |
2003 | 65 | 47 | 42 |
2004 | 70 | 54 | 31 |
2005 | 85 | 57 | 49 |
2006 | 80 | 68 | 38 |
The difference between the total production of three cars in the year $2004$ and $2006$ is _____.
Years | Production of Car P | Production of Car Q | Production of Car R |
---|---|---|---|
2001 | 76 | 59 | 28 |
2002 | 82 | 62 | 36 |
2003 | 65 | 47 | 42 |
2004 | 70 | 54 | 31 |
2005 | 85 | 57 | 49 |
2006 | 80 | 68 | 38 |
The average production of which of the following types of cars was maximum?
Supposen(A) $= 3$ and $n ( B ) = 5 .$ find the number of elements in $A \times B$
If $f:\,\left( {3,6} \right) \to \left( {1,3} \right)$ is a function defined by $f\left( x \right) = x - \left[ {\frac{x}{3}} \right],\,then\,{f^{ - 1}}\left( x \right) = $
The tangents to the graph of the function $y=f(x)$ at the point with abscissa $x=1$ forms an angle of $\pi/6$ and the point $x=2$ an angle of $\pi/3$ and at the point $x=3$ an angle of $\pi/4$. The value of
$\displaystyle \int _{1}^{2}{f'(x)f''(x)dx}+\displaystyle \int _{2}^{3}{f''(x)dx}$
The graph of the function $\cos x\cos x(x+2)-\cos^{2}(x+1)$ is
If $f(x)=\left | \sin x \right |$, then domain of $f$ for the existence of inverse is
If $|z-1|+ |z+3| \le 8$, then the range of values of $|z-4|$ is
If all the roots of $z^3 +az^2 +bz+c=0$ are of unit modulus, then
The solution set of the equation $(x+1)^2+[x-1]^2=(x-1)^2+[x+1]^2$ where $[x]$ and $(x)$ are the greatest integer and nearest integer to $x$, is