As (–7, 0) ^{_{$\leftrightarrow $}} (x, y), where x coordinate is -7, i.e. negative and y coordinate is 0, so the point (–7, 0) lies on the negative x-axis.

In the Cartesian plane, the x-axis is the horizontal axis.

Point (- 5, 0) corresponds to (x, y). Here, x-coordinate is - 5, i.e. negative and y-coordinate is 0. $\Rightarrow$So, the point (- 5, 0) lies on the negative x-axis.

The vertical (standing) axis of a Cartesian plane is y-axis.

The horizontal and vertical axis drawn on the plane divides the whole plane into quadrants.

(–5, –4) $\Rightarrow$ Both x and y coordinates are negative. When x < 0 and y < 0, the point lies in the third quadrant. So, the point (–5, –4) lies in the third quadrant. 

As the point $\biggl(- \frac{2}{3}, 0\biggr) \leftrightarrow (x,y) $ Here, x co-ordinate is $\frac{-2}{3}$, which is negative and y co-ordinate is 0. So, the point $\biggl(- \frac{2}{3}, 0\biggr)$lies on the negative x-axis.

The meeting point of two axes in the Cartesian plane is called origin (0, 0).

The point is $\biggl(\frac{4}{5}, -2 \biggr)$. It corresponds to (x, y). When x > 0 and y < 0, the point lies in the 4^th quadrant. So, the point $\biggl( \frac{4}{5}, -2 \biggr)$ lies in the 4^th quadrant.

The point is (0, – 11) ^{_{$\leftrightarrow $}} (x, y) Here, x-coordinate is 0 and y-coordinate is – 11. So, the point lies on the negative y-axis.

The perpendicular distance of the point (6, – 5) from the x-axis will be y-coordinate but with a positive sign as distance is never negative. So, the perpendicular distance of (6, – 5) from the x-axis is 5 units.

The point (0, 3) ^{_{$\leftrightarrow $}} (x, y) Here, the x-coordinate is 0 and the y-coordinate is 3. $\therefore$ The point (0, 3) lies on the positive y-axis.

The y co-ordinate is also known as ordinate and b is the y co-ordinate of point (a, b). So, 'b' is called ordinate.

The point is (17, 9) $\leftrightarrow $ (x, y) Here, x > 0 and y > 0 and if x is positive and y is positive, then the point lies in the 1^st quadrant. So, point (17, 9) lies in the first quadrant.                                                 OR The sign of co-ordinate of a point is (+, +), which lies in 1^st quadrant. So, (17, 9) lies in the first quadrant.

As the point is (8, 0)         (8, 0) $\leftrightarrow $ (x, y) Here, x-coordinate is 8 which is greater than 0 and y-coordinate is 0, and when y-coordinate is 0, then the point lies on x–axis. As the x-coordinate is greater than 0, the point (8, 0) lies on positive x–axis.

The perpendicular distance from y–axis of any point is x co-ordinate but distance is always positive. So, the perpendicular distance of (– 7, 9) from y–axis is 7 units.

The point is (11, – 15). Here, x-coordinate is 11 > 0 and y-coordinate is – 15 < 0, and the signs of the coordinates are (+, –), which lie in the 4^th quadrant. So, the point (11, – 15) lies in the 4^th quadrant.

When x-coordinate is 0, the point lies on the y–axis. $\therefore$ The point (0, 6) lies on the positive y–axis.

The perpendicular distance from y–axis of any point is x co-ordinate but distance can never be negative. So, the perpendicular distance of (13, 12) from y–axis is 13.

The point is (– 7, 6). Here, x co-ordinate is – 7 < 0 and y co-ordinate is 6 > 0 i.e. x < 0 and y > 0, and when x is negative and y is positive, then the point lies in 2^nd quadrant. So, the point (– 7, 6) lies in the 2^nd quadrant.

As the point is (7, 0),         (7, 0) $\leftrightarrow $ (x, y) Here, x co-ordinate is 7 which is positive and y co-ordinate is 0, and when y co-ordinate is 0, then the point lies on x–axis. So, the point (7, 0) lies on positive x–axis.

The point is $\biggl( \frac{-8}{6}, \frac{-7}{3} \biggr)$. Here, x-coordinate is $\frac{-8}{6}$, which is negative, and y-coordinate is $\frac{-7}{3}$, which is also negative. i.e. x < 0 and y < 0 When x < 0 and y < 0, the point lies in the third quadrant. So, the point $\biggl( \frac{-8}{6}, \frac{-7}{3} \biggr)$ lies in the third quadrant.

The perpendicular distance of a point (- 2, - 4) from x-axis will be y co-ordinate but with a positive sign, as the distance is never negative. So, the perpendicular distance of (- 2, - 4) from x-axis is 4 units.

The point is (0, – 3). Here, y co-ordinate is – 3, which is negative and when x co-ordinate is zero, then the point lies on y-axis. So, the point (0, – 3) lies on the negative y-axis.

The point is (– 2, 5). Here, x-co-ordinate is – 2 < 0 and y co-ordinate is 5 > 0. And when x < 0 and y > 0 in the point (x, y), then the point lies in the second quadrant. So, the point (– 2, 5) lies in the 2^nd quadrant.                                                             OR The signs of the co-ordinates of point are (–, +), which lies in the 2^nd quadrant. So, the point (– 2, 5) lies in the 2^nd quadrant.

The perpendicular distance of the point (11, –9) from the x-axis will be y coordinate of the point, but with a positive sign as the distance is never negative. So, the perpendicular distance of (11, –9) from the x-axis is 9 units.

The point is (7, 3) $\leftrightarrow $ (x, y) Here, x > 0 and y > 0, and when x > 0 and y > 0, the point (x, y) lies in the first quadrant. Then, the point (7, 3) lies in the 1^st quadrant.

As the point is (6, 0),             (6, 0) $\leftrightarrow $ (x, y) Here, x co-ordinate is 6, which is positive and y co-ordinate is 0. When y co-ordinate of a point is 0, then the point lies on x-axis. So, the point (6, 0) lies on positive x-axis.

The point is (4, – 8). Here, x co-ordinate is 4 > 0 and y co-ordinate is – 8 < 0. When x > 0 and y < 0, then the point (x, y) lies in the 4^th quadrant. So, the point (4, – 8) lies in the fourth quadrant.                                                 OR The signs of co-ordinates of point are (+, –), which lies in the 4^th quadrant. So, the point (4, – 8) lies in the 4^th quadrant.

The point is (– 7, – 9). Here, x co-ordinate is – 7, which is negative and y co-ordinate is – 9, which is also negative. When x < 0 and y < 0, then the point (x, y) lies in the third quadrant. So, the point (– 7, – 9) lies in the third quadrant.                                                 OR The signs of co-ordinates of the point are (–, –), which lies in the 3^rd quadrant. So, the point (– 7, – 9) lies in the third quadrant.

Since ordered pair is written in the order (x, y), where x = x coordinate of that point and y = y coordinate of that point, so the ordered pair for point D is (11, –6). 

Because ordered pair representing any point is written as (x, y), where x = x-coordinate of that point and y = y-coordinate of that point. ^{_$\therefore$}    The ordered pair representing the point E is (11, 3).

The point B lies on y-axis; so the x-coordinate must be zero and y-coordinate must be 3. Thus, the ordered pair representing the point B is (0, 3).

 (–8, 7) represents point A on the graph.

The ordered pair representing C is (– 10, – 8) as the ordered pairs are written in the order (x, y), where x = x-coordinate of the point and y = y-coordinate of the point.

The ordered pair representing point H is (5, – 12) as ordered pairs are written in the order (x, y), where x = x-coordinate of the point and y = y-coordinate of the point.

As the ordered pair representing a point is written as (x, y), where x = x-coordinate of the point and y = y-coordinate of the point. Then, the ordered pair representing I is (3, 13).

As the ordered pair for any point is written in the form (x, y), where x = x co-ordinate of the point and y = y co-ordinate of the point. Then, the ordered pair representing F is given by (- 6, 10).

As the ordered pair representing any point is given by (x, y), where x = x co-ordinate of the point and y = y co-ordinate of the point. Then, the ordered pair representing J is given by (6, 6).

As the ordered pair representing any point is given by (x, y), where x = x co-ordinate of that point and y = y co-ordinate of that point. Then, the ordered pair representing G is given by (- 5, - 10).