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Genetics and Human Reproduction

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Haploid chromosome number is 10. What will be its monosomy?

  1. 18

  2. 19

  3. 21

  4. 17

  5. 23


Correct Option: B
Explanation:

Monosomy means 2n - 1, i.e. (2 X 10) - 1 = 20 - 1 = 19. 

‘Gametes are never hybrid’. It is a statement of the law of

  1. dominance

  2. segregation

  3. independent assortment

  4. random fertilisation

  5. linkage


Correct Option: B
Explanation:

‘Gametes are never hybrid’. It is a statement of law of segregation. 

A Barr body is present in a male child. The syndrome most likely to occur is

  1. Klinefelter’s syndrome

  2. Down’s syndrome

  3. Turner's syndrome

  4. Edward’s syndrome

  5. Trisomy


Correct Option: A
Explanation:

A normal female with XX chromosomes has one Barr body. A normal male (XY) has none. Abnormal males with three XXY (Klinefelters' syndrome) have one Barr body.

DNA generally acts as a template for the synthesis of

  1. protein only

  2. DNA only

  3. RNA only

  4. RNA and DNA both


Correct Option: D
Explanation:

DNA generally acts as a template for the synthesis of DNA during replication and RNA during transcription. DNA does not act as a template for the synthesis of protein.

When chromosome sets are present in multiples of ‘n’, the condition is called

  1. polyploidy

  2. aneuploidy

  3. euploidy

  4. diploidy

  5. monoploidy


Correct Option: C
Explanation:

When chromosome sets are present in multiples of ‘n’, the condition is called euploidy.

A husband and wife have normal vision but fathers of both of them were colourblind. Probability of their first daughter to be colour blind is

  1. 25%

  2. 50%

  3. 75%

  4. 0%


Correct Option: D
Explanation:

A husband and wife have normal vision but father of both of them were colourblind. Probability of their first daughter to be colour blind is 0. Colour blindness is a sex linked recessively inherited disorder. Normal man has normal x and y chromosomes. Carrier female have one normal x and one abnormal x chromosome.The probability of their son to get colour blindness is 50%.

Secondary spermatocytes and spermatids are

  1. diploid

  2. triploid

  3. tetraploid

  4. haploid


Correct Option: D
Explanation:

Secondary spermatocytes and spermatids are haploid.

Crossing over is advantageous because it brings about

  1. linkage

  2. inbreeding

  3. stability

  4. variation


Correct Option: D
Explanation:

Crossing over is advantageous because it brings about recombination or variation.

The average length of human ovary is

  1. 5-6 cm

  2. 1-2 cm

  3. 2-4 cm

  4. 0.5-1cm


Correct Option: C
Explanation:

The average length of human ovary is 2-4 cm.

In human uterus, endometrium is maintained by the secretion of

  1. oxytocin

  2. testosterone

  3. estrogen

  4. progesterone


Correct Option: D
Explanation:

In human uterus, endometrium is maintained by the secretion of progesterone.

Which of the following cells secrete testosterone?

  1. Sertoli cells

  2. Leydig cells

  3. Germ cells

  4. Chondrocytes


Correct Option: B
Explanation:

Leydig cells secrete testosterone.

The number of testicular compartments in human testis is

  1. 250

  2. 50

  3. 350

  4. 150


Correct Option: A
Explanation:

Each testis has about 250 testicular compartments.

How many types of gametes you expect from the genotype AaBb?

  1. 4

  2. 8

  3. 1

  4. 2


Correct Option: A
Explanation:

AaBb individual can produce 2gametes, i.e. four gametes.

The genetic material in HIV is

  1. double stranded RNA

  2. single stranded RNA

  3. double stranded DNA

  4. single stranded DNA


Correct Option: B
Explanation:

The genetic material in HIV is single stranded RNA.

Mendel's laws were rediscovered by

  1. Lamarck, de Vries and Correns

  2. Hugo de Vries, Correns and Tschermak

  3. Morgan, Beadle and Tatum

  4. Hugo de Vries, Morgan and Correns


Correct Option: B
Explanation:

Mendel's laws were rediscovered by Hugo de Vries, Correns and Tschermak.

The ratio 1 : 1 : 1 : 1 is obtained from a cross between the parents

  1. RRYY x rryy

  2. RRYY x rrYy

  3. RRYY x Rryy

  4. RrYy x rryy


Correct Option: D
Explanation:

The cross RRYY x rryy cannot have the ratio 1 : 1 : 1 : 1.

Which of the following is a hormone releasing IUD?

  1. CuT

  2. Cu7

  3. Multiload 375

  4. LNG-20


Correct Option: D
Explanation:

LNG-20 is a hormone releasing IUD.

The sequence of four nitrogen bases which form the code words for DNA language is

  1. UTAC

  2. ACTU

  3. AGCU

  4. ATCG


Correct Option: D
Explanation:

The four nitrogenous bases in DNA are the purines: adenine (A), guanine (G), and the pyrimidines: cytosine (C) and thymine (T).

Spermatogenesis begins during puberty due to the increased secretion of

  1. FSH

  2. LH

  3. GnRH

  4. prolactin


Correct Option: C
Explanation:

Spermatogenesis begins during puberty due to the increased secretion of GnRH.

Saheli is a

  1. contraceptive pill for male

  2. contraceptive pill for female

  3. barrier method

  4. implant


Correct Option: B
Explanation:

Saheli is a once-in-a-week pill used by females.

Okazaki fragments are

  1. short DNA fragments on the lagging strand

  2. short DNA fragments on the leading strand

  3. RNA primers required for initiation of DNA synthesis

  4. DNA fragments produced due to radiation action


Correct Option: A
Explanation:

Okazaki fragments are short DNA fragments on the lagging strand. Synthesis of the lagging strand requires working in relatively small, discontinuous stretches. These discontinuous stretches are synthesised just as the leading strand, by the addition of new nucleotides one at a time to the 3′ end of the new strand, but the synthesis of this new strand moves in the direction opposite to that in which the replication fork is moving. These stretches of new DNA for the lagging strand are called Okazaki fragments.

GIFT stands for

  1. Gamete Interfallopian Transfer

  2. Gamete Interfallopian Tubules

  3. Gamete Intrafallopian Transfer

  4. Gamete Intrafallopian Tubules


Correct Option: C
Explanation:

GIFT stands for “Gamete Intrafallopian Transfer”. 

In the F2 generation of a dihybrid cross,

  1. 4 phenotypes appear in the ratio 9 : 3 : 3 : 1, if the loci are linked

  2. 4 phenotypes appear in the ratio 9 : 3 : 3 : 1, if the loci are unlinked

  3. 2 phenotypes appear in the ratio 3 : 1, if the loci are unlinked

  4. 3 phenotypes appear in the ratio 1 : 2 : 1, if the loci are unlinked


Correct Option: B
Explanation:

In the F2 generation of a dihybrid cross, 4 phenotypes appear in the ratio 9 : 3 : 3 :1, if the loci are unlinked.

Skin colour inheritance in man is

  1. monogenic

  2. polygenic

  3. sex-linked

  4. multiple allelic


Correct Option: B
Explanation:

Skin colour inheritance in man is not monogenic, but it is polygenic, controlled by many genes like AABBCC, aabbcc, etc.

Which of the following did not constitute the seven contrasting pairs of characters noticed by G. J. Mendel in pea?

  1. Height of plants

  2. Shape of leaves

  3. Colour of seeds

  4. Shape of pod


Correct Option: B
Explanation:

The seven characters studied by Mendel are: Plant height, Flower position, Pod shape, Pod colour, Flower colour, Seed shape and Seed colour. Shape of leaves is not considered by Mendel.

If the blood groups of parents are AB and O, the possible blood group(s) of children is/are

  1. only O

  2. only AB

  3. both AB and O

  4. either A or B


Correct Option: D
Explanation:

Blood group can either be A or B as both are dominant over O.

The person with Turner’s syndrome has

  1. 44 autosomes and XXY sex chromosomes

  2. 44 autosomes and XO sex chromosomes

  3. 44 autosomes and XYY sex chromosomes

  4. 44 autosomes and XXX sex chromosomes


Correct Option: B
Explanation:

This is Turner's syndrome.

The sex of a fruitfly is determined by

  1. Y chromosome

  2. X and Y chromosomes, the male being XY

  3. the number of X chromosomes, the male being XO

  4. Z and W chromosomes, the male being ZZ


Correct Option: B
Explanation:

The sex of a fruitfly is determined by X and Y chromosomes, the male being XY.

The special unwinding enzyme that helps in breaking the weak hydrogen bond which holds the two strands of DNA is

  1. Primase

  2. DNA ligase

  3. DNA polymerase

  4. Helicase


Correct Option: D
Explanation:

The special unwinding enzyme that helps in breaking the weak hydrogen bond which holds the two strands of DNA is helicase.

The exchange of chromosomes segments between non-homologous chromosomes is called

  1. translocation

  2. deletion

  3. frame shift

  4. duplication


Correct Option: A
Explanation:

Sometimes, a segment of a chromosome detaches and unites with another non-homologous chromosome. Such an inter-chromosomal rearrangement is called translocation.

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