If P is the momentum, then its kinetic energy is K = p²/2m. Initial momentum is P₁ = 100, then final momentum is P₂ = 200. Now K2/K1 = P²₂/P₁² = 40000/10000 = 4. That means Kinetic energy increases by 300%. The correct answer is (4)

Power P = Force X Velocity = (2i+3j+4k). (3i-2j+5k) = 6 - 6 + 20 = 20J The correct answer is (1)

Rest mass energy is E = m0c2 = 1.5 x (3x108)2 = 13.5 x 1016  J. The correct answer is (3) 

The zeros in the middle part of the number are taken as significant figures. Hence the number of significant figures is 5

 The unit of Stefan's constant is watt m^-2 K^-4

Work done = Force X displacement = 100 X 5 = 500 J Change in KE = 400 J Hence the energy lost in friction is 500 J - 400 J = 100 J

Work done  = Force . Displacement = (2i + 3j + 4k) . (3i - 2j + 5k) = 6-6+20 = 20 J

Volume = length X breadth X height = 1.45 X 1.25 X 1.37 = 2.483125After rounding off, we have 2.48

Work done = Force X displacement, Hence the area of Force - Displacement curve gives the work done

Modulus of Elasticity = Stress / Strain,Since strain has no units. Modulus of elasticity has dimensions similar to stress

Rolling friction is the least.

Time of flight T = 2u/g,  u is the initial velocity. Hence the answer is option (1)

Moment of inertia I = MR², hence the answer is (2)

Any type of energy and workdone is a scalar quantity, hence correct answer is (2)

Momentum P = mv = 5000 X 75 = 375000 kg - m/sec

Torque = r X F,  Torque is the moment of force

The frictional force is independent of the area of the contact surface. Hence the answer is (4)

Centre of mass of a body is the point at which whole mass of the body is concentrated

The spring wound in watch is strained. Hence the energy is Potential.

The centre of mass of the body may lie on the surface of the body or outside or inside the body

Law of conservation of angular momentum L = Iw = constant

CV² is the energy stored in the capacitor. So its dimensional formula is same as that of Work or Energy. The correct answer is (4).

Electric Field intensity E = F/q = MLT^-2/ iT Hence the answer is (1)  

The work done is W = mgh = 1000 X 9.8 X 3 = 29,400 J The correct answer is (2)  

x = at + bt² - ct³ [L] = a[T] + b[T²] - c[T³] [a] = LT^-1 [b] = LT^-2 [c] = LT^-3