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Description: Chemistry Atomic Structure and Chemical BondingInorganic ChemistryThe Solid StateTransition ElementsCoordination Compounds and OrganometallicsChemistryOrganic ChemistryAldehydes and KetonesBiomoleculesAlcohols and Phenols
Number of Questions: 20
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Tags: Chemistry Atomic Structure and Chemical Bonding Inorganic Chemistry The Solid State Transition Elements Coordination Compounds and Organometallics Organic Chemistry Aldehydes and Ketones Biomolecules Alcohols and Phenols
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Which of the following has the largest number of molecules?

  1. 54 g of H2O

  2. 88 g of CO2

  3. 54 g of N2O5

  4. 30 g of NH3

  5. 64 g of CH3OH

Show answer
Correct Option: A
Explanation:

54 g of H2O = 3 moles of H2O = 3 x 6.023 x 1023 molecules of H2O

Which of the following statements is/are TRUE? (1) Total number of orbitals in a shell with principal quantum number ‘n’ is n2. (2) Azimuthal quantum number determines the orientation of the orbital. (3) Stark effect is splitting of spectral lines under the influence of electric field. (4) Zeeman effect is splitting of spectral lines under the influence of magnetic field.

  1. Only 1

  2. Only 1 and 2

  3. Only 1, 3 and 4

  4. Only 2 and 3

  5. Only 2 and 4

Show answer
Correct Option: A
Explanation:

Total number of orbitals in a shell with principal quantum number ‘n’ is n2.

Which of the following spectral series lies in near infra-red region?

  1. Lyman series

  2. Balmer series

  3. Paschen series

  4. Brackett series

  5. Pfund series

Show answer
Correct Option: C
Explanation:

Yes, it is correct. Paschen series lies in near infra-red region.

Which of the following complexes has normal spinel structure? P. NiFe2O4 Q. Mn3O4 R. Fe3O4 S. MgAl2O4

  1. Only P and Q

  2. Only P and R

  3. Only Q and R

  4. Only Q and S

  5. Only R and S

Show answer
Correct Option: D
Explanation:

Mn3O4 and MgAl2O4 have normal spinel structures.

Which of the following first row transition metal ions has no unpaired electrons?

  1. Fe3+

  2. Zn2+

  3. Cu2+

  4. Co3+

  5. Ni2+

Show answer
Correct Option: B
Explanation:

Yes, it is the correct answer. Zn2+: [Ar] 3d10; No unpaired electrons

Which of the following transition metal ions is diamagnetic?

  1. Sc3+

  2. Ti2+

  3. Cr3+

  4. Ni3+

  5. Cu2+

Show answer
Correct Option: A
Explanation:

Sc3+ has d0 configuration. Due to lack of unpaired electrons, Sc3+ is diamagnetic.

Which of the following are diamagnetic?

  1. C2
  2. N2
  3. O2
  4. F2

  1. Only 1 and 2

  2. Only 1 and 3

  3. Only 2 and 3

  4. Only 2 and 4

  5. Only 1 and 4

Show answer
Correct Option: C
Explanation:

Yes, both are diamagnetic. N2 (14 e-) : σ1s2 ϭ*1s2 ϭ2s2 ϭ*2s2 ϭ2pz2 π2px2 π2py2 No unpaired electron, diamagnetic

O2 (16 e-) : ϭ1s2 ϭ*1s2 ϭ2s2 ϭ*2s2 ϭ2pz2 π2px2 π2py2 ϭ*2pz2 No unpaired electron, diamagnetic

Which of the following statements is/are FALSE? P. EDTA is tetradentate. Q. Porphyrin in heme is hexadentate. R. Ethylene diamine is bidentate. S. Sulphite is ambidentate.

  1. Only P and Q

  2. Only P and R

  3. Only P and S

  4. Only Q and R

  5. Only R and S

Show answer
Correct Option: A
Explanation:

EDTA is a hexadentate chelating agent, which is able to bond through six sites. Porphyrin in heme is a tetradentate chelating ligand.

Which of the following transition metals have completely filled 4d-orbital? P. Niobium Q. Molybdenum R. Palladium S. Cadmium

  1. Only P and Q

  2. Only P and S

  3. Only Q and R

  4. Only Q and S

  5. Only R and S

Show answer
Correct Option: E
Explanation:

Palladium (46Pd): [Kr] 4d10 5s0 Cadmium (48Cd): [Kr] 4d10 5s2 Both Pd and Cd have completely filled 4d-orbital.

Which of the following transition metal ions have four unpaired electrons?

  1. Cr3+
  2. V3+
  3. Fe2+
  4. Co3+

  1. Only 1 and 2

  2. Only 1 and 3

  3. Only 2 and 3

  4. Only 2 and 4

  5. Only 3 and 4

Show answer
Correct Option: E
Explanation:

It is correct. Fe2+: [Ar] 3d6; 4 unpaired electrons Co3+: [Ar] 3d6; 4 unpaired electrons

Which of the following substituents are m-directing?

  1. -CHO
  2. -CCl3
  3. -CH3
  4. -NH2

  1. Only 1 and 2

  2. Only 1, 2 and 3

  3. Only 1 and 3

  4. Only 2 and 4

  5. Only 2, 3 and 4

Show answer
Correct Option: A
Explanation:

Yes, it is correct. -CHO is m-directing due to –R effect. -CCl3 is m-directing due to –I effect.

The enzyme carbonic anhydrase contains

  1. cobalt

  2. copper

  3. iron

  4. zinc

  5. magnesium

Show answer
Correct Option: D
Explanation:

The active site in carbonic anhydrase contains zinc.

Which of the following complexes are diamagnetic in nature? P. [CoF6]3- Q. [Fe(CN)6]4- R. Zn(H2O)6]2+ S. [Cr(H2O)6]3+

  1. Only P and Q

  2. Only P and S

  3. Only Q and R

  4. Only Q and S

  5. Only R and S

Show answer
Correct Option: C
Explanation:

It is incorrect. [Fe(CN)6]4- is an inner orbital complex with octahedral geometry (d2sp3 hybridisation); No unpaired electrons; diamagnetic

Zn(H2O)6]2+ is an outer orbital complex with square planar geometry (sp3d2 hybridisation); No unpaired electrons; diamagnetic

Which of the following compounds will undergo Cannizzaro reaction? P. (CH3)3C-CHO Q. C6H5CHO R. C6H5CH2CHO S. CH3CH2CHO

  1. Only P and Q

  2. Only P and R

  3. Only Q and R

  4. Only Q and S

  5. Only R and S

Show answer
Correct Option: A
Explanation:

Aldehydes having no alpha hydrogen, when heated with conc. alkali, undergo self-oxidation-reduction to yield a mixture of corresponding alcohol and carboxylate salt. This reaction is known as Cannizzaro reaction. Since (CH3)3C-CHO and C6H5CHO do not have alpha hydrogen, they will undergo Cannizzaro reaction.

Which of the following compounds is the most difficult to undergo electrophilic substitution reaction?

  1. Chlorobenzene

  2. Phenol

  3. Toluene

  4. Nitrobenzene

  5. Bromobenzene

Show answer
Correct Option: D
Explanation:

Nitrobenzene has a strong deactivating nitro (electron withdrawing group) group,  which makes its electrophilic substitution reactions quite difficult.

Salts of which metal are used in the treatment of gastric ulcers?

  1. Bi

  2. Gd

  3. Au

  4. Sb

  5. Ba

Show answer
Correct Option: A
Explanation:

Bi (III) salts are used in the treatment of gastric ulcers.

Which of the following alcohols reacts the most rapidly with the Lucas reagent?

  1. Methanol

  2. Benzyl alcohol

  3. 2-Methyl-2-butanol

  4. 2-pentanol

  5. Isobutanol

Show answer
Correct Option: C
Explanation:

2-Methyl-2-butanol is a tertiary alcohol (tertiary alcohols react immediately with Lucas reagent).

Match column – I (compounds) with column – II (C-C bond length) ||| |---|---| |Column – I |Column – II| |A. Ethane|1. 120 pm| |B. Ethene|2. 134 pm| |C. Ethyne|3. 139 pm| |D. Benzene|4. 154 pm|

  1. A - 1, B - 2, C - 3, D - 4

  2. A - 1, B - 4, C - 2, D - 3

  3. A - 2, B - 4, C - 3, D - 1

  4. A - 4, B - 2, C - 1, D- 3

  5. A - 4, B - 1, C - 2, D - 3

Show answer
Correct Option: D
Explanation:

Yes, this is the correct answer. C-C bond length in ethane is 154 pm. C-C bond length in ethene is 134 pm. C-C bond length in ethyne is 120 pm. C-C bond length in benzene is 139 pm.

In the complexes [Ag(CN)2]-, [Ni(CN)4]2- and[CoCl4]2-, the hybridisation of Ag, Ni and Co atoms are ______________ respectively.

  1. sp, dsp2 and sp3

  2. sp3, dsp2 and sp

  3. dsp2, sp3 and sp

  4. dsp2, sp and sp3

  5. sp3, sp and dsp2

Show answer
Correct Option: A
Explanation:

Yes, it is correct. [Ag(CN)2]- is linear : hybridisation sp  [Ni(CN)4]2- is square planar : hybridisation dsp2 [CoCl4]2- is tetrahedral : hybridisation sp3

Match column – I (catalyst) with column – II (formulae) ||| |---|---| |Column – I |Column – II| |P. Ziegler-Natta catalyst|1. TiCl4 + Et3Al| |Q. Wilkinson’s catalyst|2. PtO2| |R. Adam’s catalyst|3. (Ph3P)3RhCl| |S. Lindlar’s catalyst|4. Pd-BaSO4 + Sulphur|

  1. P - 1, Q - 2, R - 3, S - 4

  2. P - 1, Q - 3, R - 2, S - 4

  3. P - 2, Q - 4, R - 3, S - 1

  4. P - 2, Q - 3, R - 4, S - 1

  5. P - 4, Q - 3, R - 2, S - 1

Show answer
Correct Option: B
Explanation:

Yes, it is correct. Ziegler-Natta catalyst: TiCl4 + Et3Al Wilkinson’s catalyst: (Ph3P)3RhCl Adam’s catalyst: PtO2 Lindlar’s catalyst: Pd-BaSO4 + Sulphur

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