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Chemical Bonding

Description: Shape of molecules hybridisation bonding Geometry of Molecules,VSEPR ModelVSEPR TheoryChemical Bonding and Molecular StructureChemical Bonding and Molecular Structure
Number of Questions: 15
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Tags: Shape of molecules hybridisation bonding Geometry of Molecules,VSEPR Model VSEPR Theory Chemical Bonding and Molecular Structure
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Which of the following molecules/ions has the maximum number of lone pairs?

  1. XeF2

  2. CO2

  3. XeF5-

  4. ClF3

  5. TiCl4


Correct Option: A
Explanation:

XeF2 has three lone pairs of electrons with linear geometry.

Which of the following pairs is not correctly matched?

  1. XeF4 - tetrahedral

  2. SF4 - seesaw

  3. Wl6 - octahedral

  4. BrF3 - T-shaped

  5. XeOF4 - square pyramidal


Correct Option: A
Explanation:

XeF4 has two lone pairs of electrons with square planar shape.

Which of the following molecules/ions possess bent geometry?

  1. I3-
  2. XeF2
  3. H2O
  4. SO2
  1. Only (1) and (2)

  2. Only (2) and (3)

  3. Only (3) and (4)

  4. (1), (2) and (3)

  5. (2), (3) and (4)


Correct Option: C
Explanation:

(3) and (4) have bent shapes.

Which of the following molecules bears no lone pair of electrons with linear shape?

  1. XeF2

  2. CCl2

  3. CdI2

  4. XeF4

  5. PbCl2


Correct Option: B
Explanation:

CCl2 has one lone pair of electrons with bent geometry.

Which of the following molecules bears one lone pair on the central atom with bent shape?

  1. SO2

  2. F2O

  3. H2O

  4. XeF2

  5. O3


Correct Option: A
Explanation:

The molecules which have two bond pairs and one lone pair of electrons with bent geometry are SO2, CCl2 , etc. The molecules which have two bond pairs and two lone pair of electrons with bent shape are H2O, F2O, O3, etc.

Which of the following pairs are incorrectly matched?

P. NH3 - Trigonal planar Q. SO3 - Trigonal planar R. XeCl2 - Linear geometry S. XeF5- - Trigonal bipyramidal

  1. (P) and (Q)

  2. (Q) and (R)

  3. (R) and (S)

  4. (P) and (R)

  5. (P) and (S)


Correct Option: E
Explanation:

Both are incorrectly matched pairs.

Which of the following statements is/are incorrect?

(P) Both XeF2 and OF2 molecules are identical in bond pairs and lone pairs, but are different in their shapes. (Q) NO3-, BF3 and SO3 possess identical geometry. (R) The bond angle in formaldehyde (H-C=O) is greater than that in ethylene (H-C=C).

  1. Only (P)

  2. Only (Q)

  3. Only (R)

  4. Both (P) and (Q)

  5. Both (Q) and (R)


Correct Option: A
Explanation:

Only statement (P) is incorrect.

Match the following:

 
Column - I
Column - II
A. WBr2F4 1. Seesaw
B. TeF4 2. Octahedral
C. XeO4 3. Tetrahedral
D. XeOF5- 4. Pentagonal pyramidal
5. Square planar
  1. A - 2, B - 1, C - 3, D - 4

  2. A - 2, B - 4, C - 1, D - 5

  3. A - 5, B - 3, C - 5, D - 4

  4. A - 4, B - 1, C - 3, D - 2

  5. A - 2, B - 5, C - 4, D - 3


Correct Option: A
Explanation:

The representation of codes: A - 2, B - 1, C - 3, D - 4 is correct.

Which of the following statements is/are false?

P. IF8- has a square antiprismatic shape. Q. IF7 bears zero lone pairs of electrons and possesses pentagonal bipyramidal geometry. R. SnCl2 has one lone pair of electrons and a linear shape. S. IOF3 has seesaw geometry.

  1. Only (P)

  2. Both (P) and (Q)

  3. Both (Q) and (R)

  4. Both (R) and (S)

  5. Only (R)


Correct Option: E
Explanation:

Only statement (R) is false.

Which of the following pairs has square planar geometry?

  1. SCl2, XeF2

  2. SnBr2, SeF2

  3. SCl4, CH4

  4. XeF4, ICl4-

  5. TiCl4, XeO4


Correct Option: D
Explanation:

XeF4 and ICl4- have two lone pairs of electrons with square planar shape.

The geometry of carboplatin is

  1. linear

  2. trigonal planar

  3. tetrahedral

  4. square planar

  5. octahedral


Correct Option: D
Explanation:

In square planar complexes, the geometry is prevalent for transition metal complexes with d8 configuration. Thus, the central atom (Pt) in carboplatin has dsp2 hybridisation with square planar geometry.

How many sigma and pi bonds does calcium carbide have?

  1. One sigma and one pi

  2. Two sigma and one pi

  3. One sigma and two pi

  4. Two sigma and two pi

  5. Three sigma and two pi


Correct Option: C
Explanation:

It contains one sigma and two pi bonds.

Which of the following sets of atomic orbitals represent(s) the formation of a square planar complex?

  1. s, px, py, pz

  2. s, px, py, pz, d

  3. s, px, py, pz, d, d

  4. d, s, px, py

  5. Both (3) and (4)


Correct Option: D
Explanation:

dsp2 hybridisation results in the formation of complexes with square planar geometry.

Match the following:

 
Group - I (molecules/ions)
Group - II (corresponding shapes)
P. BrF3 1. Pyramidal
Q. XeOF5- 2. Bent
R. SeO32- 3. T-shaped
S. Cl2O 4. Pentagonal pyramidal
5. Trigonal planar
  1. P - 3, Q - 4, R - 1, S - 2

  2. P - 2, Q - 4, R - 1, S - 5

  3. P - 5, Q - 1, R - 4, S - 2

  4. P - 2, Q - 3, R - 1, S - 4

  5. P - 2, Q - 3, R - 5, S - 1


Correct Option: A
Explanation:

The correct answer is: P - 3, Q - 4, R - 1, S - 2

Match the following:

   
List - A
List - B
List - C
P. IOF52- 1. Square planar i. 1
Q. XeCl2 2. Pentagonal pyramidal ii. 2
R. SbI5 3. Linear iii. 0
S. BrF4- 4. Trigonal bipyramidal iv. 3
  1. P - 3 - i, Q - 2 - iv, R - 4 - iii, S - 1 - ii

  2. P - 2 - i, Q - 3 - iv, R - 1 - iii, S - 4 - ii

  3. P - 2 - i, Q - 3 - ii, R - 1 - iii, S - 4 - iv

  4. P - 2 - i, Q - 3 - iv, R - 1 - ii, S - 4 - iii

  5. P - 2 - i, Q - 3 - iv, R - 4 - iii, S - 1 - ii


Correct Option: E
Explanation:

The correct answer is: P - 2 - i, Q - 3 - iv, R - 4 - iii, S - 1 - ii

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